Scale of FT (longish and contains physics......)

2 posts ยท Nov 19 1996 to Nov 19 1996

From: Adam Delafield <A.Delafield@b...>

Date: Tue, 19 Nov 1996 10:39:16 -0500

Subject: RE: Scale of FT (longish and contains physics......)

Date sent:  19-NOV-1996 16:36:18

> There is actually enough information in More Thrust to calculate a

> On page 13 of More Thrust we have the rules for planetary orbits. If

Errm.. Are you all right? I know a good psychiatrist if you want their phone
number.

> But wait, I hear you muttering, surely the rules in More Thrust are

In this version, we don't have planetary gravity as a factor (no orrbit to sit
in) so we can't do the same maths as before. Although the ranges would be
smaller.

From: Steve Pugh <steve@p...>

Date: Tue, 19 Nov 1996 18:59:57 -0500

Subject: Scale of FT (longish and contains physics......)

There is actually enough information in More Thrust to calculate a time and a
distance scale for Full Thrust. The results are somewhat surprising.

On page 13 of More Thrust we have the rules for planetary orbits. If
we follow the sugestions there and take an Earth-type planet to have
a radius of 6" then we can get to work.

The radius of the Earth if 6,378 km. straight away we have our distance scale
1" = 1063 km. We can round it down to 1000km, but won't for reasons that will
be explained later.

Time for a bit of physics. One outcome of Newton's Laws of motion and
gravity is that for a circular orbit T^2 = (4 * Pi^2 * r^3) / G * M
where T = the period of revolution r = radius of the orbit G = Gravitational
constant M = mass of object being orbited (ie the planet) In this case r = 12"
= 12,756,000 m and M = 6 x 10^24 kg Hence, T = 14309 s

Now a ship in this orbit moves 6" a turn around the circumference of a 12"
radius circle. circumference = 2 * pi * 12 = 75.398" At 6" per turn 1 orbit =
12.566 turns. 12.566 turns = 14309 s And so 1 turn = 1138.7 s = 18.98 minutes

So we have our time and distance scales. Now we can calculate some derived
quantities. How much acceleration does 1 point of thrust represent? If we
assume thrust is applied over the entire turn then
this formula applies-
acceleration = change in velocity / time
1 thrust = 1" / 1 turn squared
         = 1,063,000 / 1138.7 ^2
         = 0.8198 m/s^2
So what? This is nearly exactly one twelth of 1g! If we had made 1" = 1000km
then it would have thrown this neat coincidence out. If we make the time 19
minutes (1140s) then it makes it even closer.

There is a problem. Say a ship starts from rest and accelerates at
this velocity. After 1 turn it is moving at 1"/turn. By the rules
it should have moved 1". By physics it should have moved 1/2".
The only way the rules can be correct physically is if a _very_
large acceleration was maintained for a _very_ short period of time.
However, if we apply one of the golden rules of Full Thrust, "always round
things up" we can achieve a solution. A thrust of 8 must move the ship by just
over 7".

This comes out with an acceleration applied for 1/4 of a turn and 1
thrust now equals 1/3g.
A thrust 8 escort can put out a thrust of 8/3g which is fairly good
for what a human crew could stand for extended periods and still function.

Summary of what we've got so far: 1" = 1063 km 1 Turn = 19 minutes
1 Thrust  =  1/3g applied for 4.75 minutes

The 36" range of pasive sensors and A batteries is equivalent to 13% of a
light second, which when coupled with the length of the turn rather spoils the
thread about targetting. There's enough time to
perform over 2000 ping-analyse-shoot cycles in one turn. Is that
enough to give you a 50% chance of hitting?

To move at 1% of the speed of light a ship would need a velocity of
over 3000"/turn!

At this scale our sun would have a radius of 655"!

But wait, I hear you muttering, surely the rules in More Thrust are optional,
what about Jim Webster's idea of defining one table edge as the planet's
atmosphere?

Well, this makes all the ranges much smaller. If we assume that the short edge
of a table 4' = 48" is the diameter of a planet. Then a
new scale emerges 1" = 265 km or 1/4 of what we had before.
How we scale time and thrust in this case is trickier as we have no data on
orbits. But if we assume that this scale implies a rather low level of
technology then gravity control is unlikely and our vessels will have to
operate at thrusts that won't cripple the crew. So we keep
the thrust at 1/3g. This gives us 1 turn = 9.5 minutes or half of our
previous value. If the planet is wider than the table then the scale is
further reduced.

(NB For constant acceleration the time will scale as the square root of the
scaling on the distance.)

That's quite enough for now.