[GZG] lessons in dice

One quick point:

Rolling 1 dice for 2 sixes or 3 sixes versus rolling 2 or 3 dice for the
same result -
equal probability!

Proof:

1 dice for two sixes in 2 rolls:
Chance of getting a 6: 1/6.
Change of getting 2 in a row: 1/6 * 1/6 = 1/36

2 dice for two sixes in one roll:
Chance of getting a single 6 on one die: 1/6
Chance of getting both dice as sixes: 1/6 * 1/6 = 1/36

Expand this to three dice, and you have:
1 dice, rolled 3 times, for 6, 6, 6: 1/6 * 1/6 * 1/6 = 1/216
3 dice, rolled once, for 6, 6, 6: 1/6 * 1/6 * 1/6 = 1/216

I figured most of us know that rolling two dice yields 36 possible combos,
only one of which is double six. Similarly, roling 3 dice yields only one way
to generate an 18 for your AD&D character's strength, one way out of 216
possibilities. That works out to be just the same as the odds of rolling 1 die
for two sixes in a row or for three sixes in a row (respectively). So it
doesn't matter if you throw Nd6 or d6 N times to generate X number of sixes.
This logic applies beyond the number of dice = 3.

Tom B (just to settle that side point) (Can we stop now, BTW, or do we need to
open a new

for thoses interessted in probabilities in FT I'd calculate long ago the math
expectancy and standard gap of some weapons:

http://perso.wanadoo.fr/new.savoy/math.html

the reroll possibilies are included and were dealt as infinite limit of
serie's sum (don't know how to say that in proper english lool)

/L

> One quick point:
http://lists.csua.berkeley.edu/mailman/listinfo/gzg-l
> [quoted text omitted]