From: Laserlight <laserlight@q...>
Date: Mon, 31 Jul 2000 21:57:36 -0400
Subject: Gravitational effects on orbits
Allan and I were discussing this offlist and realized there had been an oversight in a formula, so the numbers given previously were not correct. Here are the correct numbers and how to get them: > From basic physics (ie the class we took 15 to 20 years ago) we The Earth's radius we have determined to be approximately 6mu (6.375 to be picky, but we'll call it 6). So at 6mu from the center, the acceleration is 4mu/turn. Gravity drops off as the square of the increase of distance, so for a radius R from the center of the planet, the gravitational effect is 4mu/turn * (6/R)^2 . Thus at 12 mu radius, the gravitational effect is 4 * (6/12)^2 =1mu/turn. 7mu radius is close to 3mu/turn effect, and 8.5mu radius is about 2mu/turn effect. Now, the other part of the problem is that if you make the endpoint of movement the determining factor, you'll tend to crash. Let's say you swoop in and end your turn at 7 mu radius. No matter how fast you're going and no matter what the direction, gravity grabs you and pulls you 3mu towards the center of the planet. 7mu (your altitude) - 3mu (gravity effect) abruptly meets 6mu (planetary radius) with a severe detrimental effect on your hull. Let me say it again--no matter how fast or what direction you're going in, you crash. Traveler took the critical point to be the midpoint of the move instead of the endpoint, and I suspect that may work better.